Solving Mike's Crate Motion After 2 Secs

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SUMMARY

Mike is dragging a 20.0 kg crate with a force of 40 N while facing a frictional force of 25 N. The net force (FNET) acting on the crate is calculated as 15 N, leading to an acceleration of 0.75 m/s². After 2 seconds, the crate's velocity is determined to be 1.5 m/s, confirming that the initial calculation was correct but the units were misrepresented. The final velocity is expressed in meters per second (m/s).

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Homework Statement


Mike is dragging a 20.0 kg crate across the floor. If he exerts 40 N force upon the crate and there is a 25 N frictional force opposing the crate's motion, how fast will the crate be moving after 2.0 seconds if it is initially at rest?


Homework Equations


FNET=ma


The Attempt at a Solution


I used FNET=ma to solve for the acceleration as follows:
FPC-FFC=ma
40-25=20a
15=20a
a=0.75m/s2

Then here's where I'm not sure if this is correct: I multiplied the acceleration 0.75m/s2 by 2.0 seconds to get 1.5m/s2.
Is this the correct answer for the question: How fast will the crate be moving after 2.0 seconds?
Thanks.
 
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cheerspens said:
Then here's where I'm not sure if this is correct: I multiplied the acceleration 0.75m/s2 by 2.0 seconds to get 1.5m/s2.
Is this the correct answer for the question: How fast will the crate be moving after 2.0 seconds?
Thanks.

Almost right. What happens when you multiply an acceleration by a time? What are the units? (You have the correct numeric answer, your units are off)
 
Oh it wouldn't be squared. So it would be 1.5m/s.
 
Exactly.
 

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