Solving Motion in Springs: A Beginner's Guide

  • Thread starter Thread starter craigthecraig
  • Start date Start date
  • Tags Tags
    Motion Springs
Click For Summary
SUMMARY

The discussion focuses on solving a physics problem involving a particle of mass m suspended by a light elastic spring with stiffness k. The equilibrium extension of the spring is denoted as d, and the equation of motion derived is x + (g/d)x = 0 for t > 0, where g represents gravitational acceleration. Participants emphasize the importance of analyzing forces at equilibrium and applying Newton's 2nd Law, particularly regarding the sign convention for displacement. This foundational understanding is crucial for correctly formulating the motion equation.

PREREQUISITES
  • Understanding of Newton's 2nd Law of Motion
  • Basic knowledge of spring mechanics and Hooke's Law
  • Familiarity with gravitational forces and their effects on mass
  • Ability to interpret and manipulate differential equations
NEXT STEPS
  • Study the principles of Hooke's Law and its application in spring systems
  • Learn how to derive equations of motion for oscillatory systems
  • Explore the concept of equilibrium in mechanical systems
  • Investigate the role of sign conventions in physics problems
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of spring systems and oscillatory motion.

craigthecraig
Messages
1
Reaction score
0
I have no idea where to start with springs,I like to blame my lecturer...
Anyway I have a past paper and there's a question that goes something like this

A particle of mass m hangs freely suspended by a light elastic spring of stiffness k.
In equilibrium, the extension of the spring is d. If x is used to measure the downward displacement of the particle beyond its equilibrium position,show that the equation of motion for the particle is
..
x+(g/d)x=0 t>0 (The first x is x double dot,or acceleration)

where g is acceleration due to gravity.

It seems like a simple enough problem,I just don't know where to begin.Any ideas?
 
Physics news on Phys.org
Start by analyzing the forces acting on the mass when it is in equilibrium. You will get an expression that will be useful later on in the question.

Then analyze the forces acting on the mass when it is pulled a further distance downward beyond equilibrium position. Use Newton's 2nd Law and take note of your sign convention! Is downward or upward the positive direction? Read the question carefully to determine this!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 8 ·
Replies
8
Views
8K
Replies
4
Views
2K
Replies
6
Views
1K
  • · Replies 21 ·
Replies
21
Views
5K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K