Solving Motor Rotation: 0 to 1800rpm in 0.49s?

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Homework Help Overview

The problem involves calculating the time required for an electric motor's rotor to accelerate from 0 to 1800 rpm under a constant torque, with specific parameters regarding the rotor's weight and dimensions. The subject area includes dynamics and rotational motion.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the moment of inertia calculation and the implications of using weight versus mass in the equations. There is a focus on unit consistency and the need to convert torque units.

Discussion Status

Some participants confirm the correctness of the 0.49 seconds answer while others suggest re-evaluating the calculations with proper unit considerations. There is acknowledgment of potential errors in interpreting weight as mass and the need for unit conversions.

Contextual Notes

Participants note the distinction between weight and mass, and the necessity of converting torque units from inch-pounds to foot-pounds. There is an emphasis on ensuring that calculations yield the correct dimensional results.

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Homework Statement


The rotor of an electric motor weighs 10 pounds and is 4 inches in diameter. What is the length of time required for the motor speed to increase from 0 to 1800rpm, assuming a constant electrical torque of 20 in-lb and zero external load during this period? Assume the rotor is a homogeneous cylinder.

Homework Equations

The Attempt at a Solution


Moment of inertia (I) of cylinder according to google is $$I=1/2 MR^2 = 1/2*10*2^2=20\\\\\
1800 rpm = \frac{1800}{60} \frac{rotations}{second} * \frac{2\pi rads}{rotation} = 188.5\\\\
20*188.5=20t\\\\
t=188.5$$
The book says the answer is 0.49 seconds. I got 188.5 seconds. Which is correct?
 
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0.49 s is correct.

Your overall approach is fine. But you are not giving enough consideration to the units of the various quantities. For example, the rotor weighs 10 pounds. But does M in the formula I = (1/2)MR2 represent weight? You should rework the problem plugging in units for each quantity in the calculation. If the units in your calculation do not reduce to seconds when you solve for t, you know you made an error.
 
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TSny said:
0.49 s is correct.

Your overall approach is fine. But you are not giving enough consideration to the units of the various quantities. For example, the rotor weighs 10 pounds. But does M in the formula I = (1/2)MR2 represent weight? You should rework the problem plugging in units for each quantity in the calculation. If the units in your calculation do not reduce to seconds when you solve for t, you know you made an error.
A slightly different take on the error... Not sure which is more helpful.
fahraynk said:
20 in-lb
The lb there does not represent mass. What does it represent?
 
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I got it. There were 2 problems. They gave me weight but I thought it was mass, so I had to divide by gravity. The other was they gave me torque in inch pounds, I had to convert it to foot pounds. Thank you both.
 

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