In the system of Problem 2-6, we need move the load by 20 degrees and bring the system to rest. Assuming a triangular speed profile of the load with equal acceleration and deceleration rates (starting and ending at zero speed). Assume a coupling efficiency of 100%. The magnitude of the electromagnetic torque (positive or negative) available from the motor is 500 Nm.
JL = 8.3 kg*m2
JM = 1.4 kg*m2
What is the time (in seconds) needed to rotate the load by an angle of 20o? Give the correct answer to 3 or more decimal places.
T(em) = [Jm + (Wl/Wm)^2 * Jl]*dw/dt
The Attempt at a Solution
I see a dt in there so I think this is my hint. I know I can set T(em) to 500. Jm is given, and I believe W (omega) of load is 3 times smaller than the motor, w/w would be (1/3)^2. But dw/dt is constant due to the triangle torque constraint isn't it? Cant integrate that right? Could someone explain how I am thinking of this wrong with a push in the right direction? Thanks.