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orangeincup

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## Homework Statement

A power screw with a pitch of 1 mm is directly coupled to a stepper motor rotating at 60 rpm. If

the efficiency of the power screw is 35%, what is the stepper motor torque required to raise a

4450 N (1000 lb) load?

## Homework Equations

P=τ*ω

τ=F*r

## The Attempt at a Solution

60rpm*2∏/60=6.28 rad/s

τ=4450*(.0005)=2.22 N-m (I assume this is wrong)

The answer is suppose to be 2.023 N-m