Solving Multivariable Limits: Evaluating $\lim_{(x,y) \to (0,0)}\frac{x-y}{x+y}$

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Homework Help Overview

The problem involves evaluating the limit of the expression \(\lim_{(x,y) \to (0,0)}\frac{x-y}{x+y}\) as the point \((x,y)\) approaches \((0,0)\). This is situated within the context of multivariable calculus, specifically focusing on limits in two dimensions.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to evaluate the limit using polar coordinates but encounters difficulty in progressing further. Some participants suggest alternative approaches, such as taking limits along specific paths (e.g., letting \(x\) approach 0 while \(y\) is held constant and vice versa).

Discussion Status

Participants are exploring different methods to evaluate the limit, with some confirming the results of their calculations. There is a recognition of differing outcomes based on the approach taken, leading to a discussion about the existence of the limit.

Contextual Notes

There is an indication that the limit may not exist based on the results obtained from different paths, but no consensus has been reached on the final conclusion regarding the limit's existence.

spacefreak
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Homework Statement


Evaluate the following limit or give a reason explaining why the limit does not exist.

[tex]\lim_{(x,y) \to (0,0)}\frac{x-y}{x+y}[/tex]

Homework Equations


[tex]x = r*\cos\theta[/tex]
[tex]y = r*\sin\theta[/tex]

The Attempt at a Solution


[tex]\lim_{r \to 0}\frac{r*\cos\theta-r*\sin\theta}{r*\cos\theta+r*\sin\theta} =<br /> \lim_{r \to 0}\frac{\cos\theta-\sin\theta}{\cos\theta+\sin\theta} =<br /> \lim_{r \to 0}\frac{1}{1+\tan\theta} - \lim_{r \to 0}\frac{1}{1+\cot\theta}[/tex]

When I get to this point, I'm stuck. How do I either find the limit or show that it doesn't exist?
 
Last edited:
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No need for polar coordinates on this one. Take the limit as x->0 while y=0 and vice versa.
 
So, to make sure I understand.

When x -> 0 while y = 0, the limit equals 1. When y -> 0 while x = 0, the limit equals -1. Therefore, the limit does not exist. Am I correct?

I appreciate your help.
 
spacefreak said:
So, to make sure I understand.

When x -> 0 while y = 0, the limit equals 1. When y -> 0 while x = 0, the limit equals -1. Therefore, the limit does not exist. Am I correct?

I appreciate your help.

Exactly.
 

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