Solving ((n+1)+2)/2^(n+1) = (n+1/2^(n+1)) + 2/2^(n+1)

[lordy12]

1. How does [((n+1)+2)/2^(n+1)]= [((n+1)/(2^(n+1)) + (n+2)/(2^n))?



2. For example: (a+b)/x = a/x +b/x



3.

Likewise, (n+1)+2/2^(n+1) = n+1/2^(n+1)) + 2/2^(n+1). How does the previous expression equal n+1/2^(n+1)) + 2/2^(n+1) when 2/2^(n+1) does not equal 2/(n+1)?

 

[Defennder]

Is this what you are trying to say:

$$\frac{n+1+2}{2^{n+1}} = \frac{n+1}{2^{n+1}} + \frac{2}{2^{n+1}}$$?

If so, it appears correct, and I don't see how the expression in your problem is true.

 

[Gib Z]

I'm not too sure what your question is either, but from what I can tell, its not true. Multiply everything by 2^(n+1), simplify, and you'll see the resulting equation is obviously false.