Solving Nature of Atoms Homework: Part (a) ionization energy Z=2

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SUMMARY

The discussion focuses on calculating the ionization energy for a helium ion (Z=2) in part (a) of the homework assignment. The correct approach involves using the equation E = -13.6 * (Z^2/n^2), where Z is the atomic number and n is the principal quantum number. For helium, with Z=2 and n=1, the ionization energy is calculated to be 54.4 eV, not the previously assumed 13.6 eV, which is specific to hydrogen. This distinction is crucial for accurately solving the problem.

PREREQUISITES
  • Understanding of ionization energy concepts
  • Familiarity with the equation E = -13.6 * (Z^2/n^2)
  • Basic knowledge of atomic structure, specifically for helium
  • Ability to interpret quantum numbers and their significance
NEXT STEPS
  • Research the ionization energies of other elements using the formula E = -13.6 * (Z^2/n^2)
  • Learn about the differences in ionization energy between hydrogen and helium
  • Explore quantum mechanics principles related to atomic structure
  • Investigate the implications of ionization energy in chemical reactions
USEFUL FOR

Students studying atomic physics, educators teaching quantum mechanics, and anyone interested in the properties of ionized atoms and their energy levels.

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Homework Statement


(a) What is the minimum energy (in electron volts) that is required to remove the electron from the ground state of an ionized atom (Z=2)? (b) What is the ionization energy for this ion?


Homework Equations


After doing what I got the answer for part (b)... but I don't know what part (a) requires. I thought this number would be 13.6 eV, but it's not. What exactly is part (a) asking?


The Attempt at a Solution



I used the equation E= -13.6*(Z^2/n^2). I plugged in 2 for Z and 1 for n.
 
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