Thank you. It was helpful. And solved.Joyal babu said:You got the energy in each state.Divide that by 1.60218e-19 you get the ionization potential of each state in eV.Now find the difference between n=2 and n=3 states.Give that as E.Find ionization potential in n=1.See what multiple of E is that.You got the answer.They gave "ionization potential in volts" to confuse you.
Volt*Q(e)=eV.In this problem both have the same numerical value.
Ionization energy is the amount of energy required to remove an electron from an atom, resulting in the formation of a positively charged ion.
Ionization energy is typically measured in units of joules (J) or electron volts (eV). It can also be expressed in kilojoules per mole (kJ/mol) for larger atoms or molecules.
Ionization energy is affected by a few key factors, including the number of protons in the nucleus, the distance between the nucleus and the outermost electrons, and the shielding effect of inner electrons.
Generally, ionization energy increases from left to right across a period in the periodic table, as the number of protons and the strength of the nuclear attraction increases. It decreases down a group, as the distance between the nucleus and outer electrons increases.
Ionization energy is an important concept in chemistry, as it can help predict the reactivity and chemical properties of elements. It is also used in various analytical techniques, such as mass spectrometry, to identify and analyze the composition of substances.