Solving Newton's Method for f(x) = 0: Step-by-Step

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Homework Help Overview

The problem involves analyzing the function f(x) = (1/x)^x - x, specifically addressing the existence and uniqueness of solutions to the equation f(x) = 0, as well as applying Newton's Method to approximate a solution.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the implications of the equation (1/x)^x = x and explore logarithmic properties to analyze the function. There is an attempt to clarify the relationship between the logarithmic forms of the equation.

Discussion Status

Some participants have provided insights and suggestions regarding the logarithmic manipulation of the equation. The original poster indicates they have resolved their initial confusion, but the discussion remains open with various interpretations being explored.

Contextual Notes

There is an indication of a need for clarification on the existence and uniqueness of solutions, as well as the application of Newton's Method, which may involve assumptions about the function's behavior.

EL ALEM
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Homework Statement


Nother Q for today:
Let f(x)= (1/x)^x - x
(a)show that f(x)=0 has a solution
(b)show that there is only one solution to f(x)=0
(c)use Newton's Method to find the second approximation x2 of the solution to f(x) =
0 using the initial approximation x1 = 1/2


Homework Equations





The Attempt at a Solution


I know how to do part C just need a little kick in the right direction for the first part.

(1/x)^x - x = 0
(1/x)^x = x
xln(1/x) = lnx
 
Last edited:
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EL ALEM said:
x \log(1/x) = \log(x)

Remember what \log(a/b) equals to? Break the pieces out.
 
How about the simple fact that 1 to any power is 1?
 
I already got it, it was late and I wasn't thinking straight, thanks for the replies though.
 

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