Solving Newton's Second Law: 3 Blocks, 667 N Force

[Momentum09]

Can somebody please give me hints as to how to approach this problem?

Three blocks are in contact with each other on a frictionless horizontal surface. [order: 2.8kg, 6kg, 7.7kg] A 667 N horizontal force is applied to the block with mass of 2.8kg. What is the net force on the block with mass 2.8kg? What is the resultant force on the block with mass 6kg?

Thank you!

 

[Weave]

Whats similar about all three blocks? They all have the same acceleration. So
F=ma ---> $$\frac{F}{block_{1}+block_{2}+bock_{3}}=a$$
You can use that information to find the answers to your other questions.

 

[Momentum09]

Thanks!
And to find the magnitude of the force between the block with mass 6kg and 7.7kg, do I subtract the net force for 6kg from that of 7.7kg?