Solving Newton's Second Law: 3 Blocks, 667 N Force

AI Thread Summary
To solve the problem involving three blocks on a frictionless surface, it's important to recognize that all blocks share the same acceleration due to the applied force. The net force on the 2.8 kg block is equal to the applied force of 667 N. Using Newton's second law (F=ma), the acceleration can be calculated by dividing the total force by the combined mass of all three blocks. To find the force between the 6 kg and 7.7 kg blocks, subtract the net force acting on the 6 kg block from the total force acting on the system. Understanding these relationships is key to solving the problem effectively.
Momentum09
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Can somebody please give me hints as to how to approach this problem?

Three blocks are in contact with each other on a frictionless horizontal surface. [order: 2.8kg, 6kg, 7.7kg] A 667 N horizontal force is applied to the block with mass of 2.8kg. What is the net force on the block with mass 2.8kg? What is the resultant force on the block with mass 6kg?

Thank you!
 
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Whats similar about all three blocks? They all have the same acceleration. So
F=ma ---> \frac{F}{block_{1}+block_{2}+bock_{3}}=a
You can use that information to find the answers to your other questions.
 
Thanks!
And to find the magnitude of the force between the block with mass 6kg and 7.7kg, do I subtract the net force for 6kg from that of 7.7kg?
 
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