Solving Number Theory Problems: Totient & Primitive Roots

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SUMMARY

This discussion focuses on solving number theory problems involving the totient function and primitive roots. The first problem requires finding all integers n such that the Euler's totient function φ(n) equals 110. The second problem involves proving that if both 2 and 3 are primitive roots modulo a prime p, then 6 cannot be a primitive root modulo p. Key insights include the relationship between prime divisors and the totient function, as well as the implications of order in modular arithmetic.

PREREQUISITES
  • Understanding of Euler's totient function (φ)
  • Knowledge of prime numbers and their properties
  • Familiarity with modular arithmetic and primitive roots
  • Basic concepts of number theory
NEXT STEPS
  • Study the properties of the Euler's totient function (φ) in detail
  • Learn about the concept of primitive roots and their significance in number theory
  • Explore the relationship between prime factorization and the totient function
  • Investigate the Jacobi symbol and its applications in proving properties of numbers
USEFUL FOR

This discussion is beneficial for students of number theory, mathematicians interested in modular arithmetic, and anyone seeking to deepen their understanding of the Euler's totient function and primitive roots.

Seiya
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Homework Statement


Hi guys, i have never taken number theory yet now I am forced to quickly understand it as it was required for a class i signed up. I need help with these problems and would greatly appreciate any hints or help in the right direction. Thanks.

1)Find with proof, all n such that totient function(n)=110

2) Suppose p is a prime and 2 and 3 are both primitive roots mod p . Prove that 6 is not primitive root mod p



Homework Equations

and

The Attempt at a Solution



I know that totient function (p) if p is a prime is p-1, but this doesn't apply here as 111 is not a prime.

I also know i can break up a number n into 2 distinct primes to get a solution but i am puzzled as to how that can help me here.


2)
I know i have to prove that 6 cannot have order of p-1 but don't know how, someone said jacubi number but the professor never mentioned that in the review so i don't think he meant it to be solved that way.

Any help appreciated, thanks.
 
Physics news on Phys.org
1) It's easy to see that if m divides n, then phi(m) divides phi(n). In particular, for every prime divisor p of n, p-1 divides phi(n)=110. A similar trick applied to p^k (with k>1) will help you determine the only possible prime factorizations of n.

2) Well, we know that there are positive integers a,b,c,d each less than p-1 such that 2^a=3, 2^b=6, 3^c=2 and 3^d=6. Try playing around to see if this implies that it's impossible that the elements 6, 6^2, ..., 6^(p-1) are all distinct. [I haven't tried this.]
 

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