Solving ODE w/ Initial Condition: Verify & Determine Particular Solution

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The discussion centers on solving the ordinary differential equation (ODE) given by y' = 1 + 36y^2, with the proposed solution y = (1/6)tan(6x + c) and the initial condition y(0) = 0. The user initially calculates the particular solution as y = (1/6)tan(6x), but encounters issues with the program not recognizing this as correct. It is confirmed that the solution is indeed correct, but the program's formatting requirements may have caused confusion. Ultimately, the program failed to list the correct answer in a multiple-choice format.

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ODE solutions :(

hey guys, I am attempting to prove this:

Verify that y is a solution of the ODE. Determine from y the particular solution satisfying the given initial condition.

y' = 1 + 36y^2 , y = (1/6)tan(6x+c) y(0) = 0

It can be seen that it is a solution

I then calculate that the particular solution for the specified point is:

y = 1/6tan6x


Can anyone see where I am going wrong here?
The program says this is not correct. I would assume c = tan^-1 0 and that follows. thanks for all help
 
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Yes, y= (1/6)tan(6x) is correct. But "programs" are notorious for insisting that an answer be in exactly the right form. If you wrote 1/6tan6x without parentheses, it may be interpreting it as 1/(6 tan(6x)) which would be wrong. Or it could be asking you for the value of c so that "0" is the correct answer.
 


Thanks HallofIvy,

Turns out it was correct, it was a multiple choice question and it turns out the program was so wrong it didnt even have the answer listed. Cheers
 

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