Solving Oscillation Problem: Find Time for Pendulum with 30m Cable

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SUMMARY

The discussion centers on calculating the period of a simple pendulum with a 30-meter cable. The formula used is T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity (9.81 m/s²). The initial calculation yielded a period of 9.61 seconds, but after a recalculation, the correct period was determined to be 11 seconds. This highlights the importance of accuracy in mathematical calculations for pendulum motion.

PREREQUISITES
  • Understanding of simple harmonic motion
  • Familiarity with the formula for pendulum period (T = 2π√(L/g))
  • Basic knowledge of gravitational acceleration (g = 9.81 m/s²)
  • Ability to perform square root and multiplication calculations
NEXT STEPS
  • Study the effects of varying cable lengths on pendulum period
  • Explore the concept of damping in pendulum motion
  • Learn about the mathematical derivation of the pendulum period formula
  • Investigate real-world applications of pendulum motion in engineering
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of pendulum motion and its mathematical principles.

Cougar1112
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A wrecking ball is suspended from a crane by a cable that is 30 m long. How much time is required for such a simple pendulum to make one complete oscillation? no picture was given to me

Ok this is a pendulum problem and its asking for time which is the period.

So I think that this formula should work since its a simple harmonic motion prob. and asking for Time.

T= 2pi[L/g]^1/2

T=2pi[30/9.81m/s]^1/2
T=9.61s

Is this correct or did I miss something.
 
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Well, the reasoning and the equation look fine, but I'm getting a different answer. You might check the calculation again.
 
yeah I made a calculation error. Now I got 11s as the time. Thanks Diane
 

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