Solving Part b of an Invertible Matrix Homework Statement

  • Thread starter Thread starter oddiseas
  • Start date Start date
  • Tags Tags
    Homework Matrix
Click For Summary

Homework Help Overview

The discussion revolves around a problem involving the invertibility of matrices, specifically focusing on the expression \(A^{-1} + 2B^{-1}\) and its inverse in terms of matrices \(A\), \(B\), and \((2A + B)^{-1}\). Participants are exploring the implications of matrix operations and properties related to invertible matrices.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various attempts to manipulate the expression for \((A^{-1} + 2B^{-1})^{-1}\) and question how to express it in terms of the given matrices. There are suggestions to multiply by certain combinations of matrices to explore potential simplifications.

Discussion Status

Some participants have provided hints and suggestions for approaching the problem, while others express confusion about the logic behind the manipulations. There is an ongoing exploration of different combinations and interpretations of the problem without a clear consensus on the next steps.

Contextual Notes

Participants note that the problem does not specify that the combination of matrices must be linear, leading to further questioning of the assumptions underlying their approaches. There is also mention of specific matrix identities that may be relevant to the discussion.

oddiseas
Messages
66
Reaction score
0

Homework Statement



a)Let A be an n*n invertible matrix. Show that the inverse of the transpose of a matrix (A^{T}) is (A⁻¹)^{T}

b)Let A,B, 2A+B be n×n matrices.Show that A⁻¹+2B⁻¹ is also invertible and express (A⁻¹+2B⁻¹)⁻¹ in terms of A, B and (2A+B)⁻¹

Homework Equations



I have done part a. I have been stuck on part b for a while. I have tried everything i can think of.



The Attempt at a Solution



I have tried revamping
(A⁻¹+2B⁻¹)⁻¹(A⁻¹+2B⁻¹)=I
(A⁻¹+2B⁻¹)⁻¹A⁻¹+ (A⁻¹+2B⁻¹)⁻¹2B⁻¹=I
(A⁻¹+2B⁻¹)⁻¹=(I-(A⁻¹+2B⁻¹)⁻¹2B⁻¹)A
Then simplified it, but the result is not in terms of the matrix (2A+B)⁻¹,A and B.
This question really has me stumped.
 
Physics news on Phys.org
Hi oddiseas! :smile:

(try using the X2 tag just above the Reply box :wink:)
oddiseas said:
b)Let A,B, 2A+B be n×n matrices.Show that A⁻¹+2B⁻¹ is also invertible and express (A⁻¹+2B⁻¹)⁻¹ in terms of A, B and (2A+B)⁻¹

I have tried revamping
(A⁻¹+2B⁻¹)⁻¹(A⁻¹+2B⁻¹)=I
(A⁻¹+2B⁻¹)⁻¹A⁻¹+ (A⁻¹+2B⁻¹)⁻¹2B⁻¹=I
(A⁻¹+2B⁻¹)⁻¹=(I-(A⁻¹+2B⁻¹)⁻¹2B⁻¹)A
Then simplified it, but the result is not in terms of the matrix (2A+B)⁻¹,A and B.
This question really has me stumped.

Hint: start with the result :wink:, and see what values of p q and r make it work …

multiply (A-1 + 2B-1) by pA + qB + r(2A + B)-1

what do you get? :smile:
 
I have multiplied (A⁻¹+B⁻¹) by what you have suggested and i get:

p+2q+qBA⁻¹+2pAB⁻¹+r(2A²+BA)⁻¹+r(2B²+4AB)⁻¹

But i still cannot see the logic. This question just seems to get longer and longer!
Could you explain to me the logic in how i should approach this question.
 
oddiseas said:
I have multiplied (A⁻¹+B⁻¹) by what you have suggested and i get:

p+2q+qBA⁻¹+2pAB⁻¹+r(2A²+BA)⁻¹+r(2B²+4AB)⁻¹

But i still cannot see the logic. This question just seems to get longer and longer!
Could you explain to me the logic in how i should approach this question.

It said (2B^(-1)+A^(-1))^(-1) is a combination of the given matrices. It didn't say it was a linear combination. You just have to fool around with combinations. Hint: what is A^(-1)*(2A+B)*B^(-1)?
 
Thanks for the reply, that helps a lot. Your'e a superstar! I will work on that and see what i can get, and then post it.
 

Similar threads

Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
3K
Replies
13
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K