Solving Physics Homework: Tension in Bow String at 30.0lb Force

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SUMMARY

The discussion focuses on calculating the tension in a bowstring when an archer pulls it back with a force of 30.0 lb at an angle of 126 degrees between the two halves of the string. The correct approach involves using the equation 2Tcos(63) = 30, leading to a tension value of approximately 33.07 lb. Previous attempts yielded incorrect values due to miscalculations in vector components. The final solution confirms that the tension in the string is indeed 33.07 lb.

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  • Knowledge of trigonometric functions, specifically cosine
  • Familiarity with the concept of tension in strings
  • Basic principles of static equilibrium
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the mechanics of tension in strings, particularly in archery contexts.

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Homework Statement


Pulling the string on a bow back with a force of 30.0lb , an archer prepares to shoot an arrow.

If the archer pulls in the center of the string, and the angle between the two halves is 126 degrees, what is the tension in the string?



2. The attempt at a solution

cos (126/2) = 30/T
T=29.5

This answer is wrong. I don't know where I messed up. I even got 66 and 60 once during trying to solve this. All of them were wrong.

Can anyone please help me out?
 
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If you draw the vectors for the two tensions, you should get two vector components in the direction opposite to the 30lb pulling force.
 
rock.freak667 said:
If you draw the vectors for the two tensions, you should get two vector components in the direction opposite to the 30lb pulling force.

I tried something like this
2Tcos(126/2) =30
T = 33.07
is it close enough?

Thanks a lot!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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