Solving Physics Problems with the Box and Banana

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Homework Help Overview

The discussion revolves around a physics problem involving a box of bananas on a horizontal surface, focusing on the forces of friction acting on the box under various conditions. The problem includes questions about static and kinetic friction coefficients, as well as the effects of applied forces.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the nature of friction forces when no external force is applied and question whether the friction force is zero in that case.
  • There is discussion about calculating the friction force when a horizontal force is applied, with some participants questioning the correct approach to find the net force and resulting acceleration.
  • Some participants express uncertainty regarding the conversion of weight to mass and its implications for calculations.

Discussion Status

Some participants have confirmed their understanding of certain parts of the problem, while others are seeking clarification on specific calculations. There is ongoing exploration of the relationships between forces and acceleration, with some guidance provided on how to approach these calculations.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is a focus on ensuring that calculations align with the principles of physics, particularly in relation to forces and motion.

EvanQ
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Homework Statement



A box of bananas weighing 40.0N rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.40 and the coefficient of kinetic friction is 0.20.

a) If no horizontal force is applied to the box and the box is at rest, how large is the friction force exerted on the box?

b) What is the magnitude of the friction force if a monkey applies a horizontal force of 6.0N to the box and the box is initially at rest?

c) What minimum horizontal force must the monkey apply to start the box in motion?

d) What minimum horizontal force must the monkey apply to keep the box moving at constant velocity once it has been started?

e) If the monkey applies a horizontal force of 18.0N, what is the magnitude of the friction force ?

f) If the monkey applies a horizontal force of 18.0N, what is the box's acceleration?


Homework Equations



F=ma

The Attempt at a Solution



a) if there is no force applied to the box, the friction force exerted is 0N? or would i times the coefficients of both static and kinetic energy with the weight of the box?

b) just the 6N applied? or the (static friction coefficient x weight) - 6N?

c) 40N x coefficient of static = 16N

d) 40N x coeff of kinetic = 8N

e) remains 8N

f) having a major mind blank over this one.

so yeh, just needing some pointers for parts a, b and f.
thanks in advance.
 
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just got part b correct, only need help with part a and f thanks.
 
For a you're right, there is 0 frictional force.

For f... what is the net force acting in the horizontal direction while the box is moving? Use this and F=ma to get the acceleration.
 
18N to the right, minus 8N to the left (kinetic friction x weight) = 10N to the right.

F=ma
10=40a
a=0.25m/s?

or am i using the wrong value for m?
 
EvanQ said:
18N to the right, minus 8N to the left (kinetic friction x weight) = 10N to the right.

F=ma
10=40a
a=0.25m/s?

or am i using the wrong value for m?

The m is wrong. 40N is the weight not the mass. Get the mass from W = mg.
 
once again on my final submission :p, so could you please just verify this is correct for me>

F=ma
10=4.08a
a=2.45m/s

thanks
 
EvanQ said:
once again on my final submission :p, so could you please just verify this is correct for me>

F=ma
10=4.08a
a=2.45m/s

thanks

Yup, only the units are wrong. :wink: 2.45m/s^2
 
sweet thanks :)
 

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