MHB Solving Polynomial Inequalities

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To solve the polynomial inequality $(x - 3)(x + 1) + (x - 3)(x + 2) \ge 0$, first factor the left-hand side to get $(x-3)(2x+3) \geq 0$. Identify the zeros of the function, which are at $x=3$ and $x=-\frac{3}{2}$. Create an interval table to determine where the product $(x-3)(2x+3)$ is positive. The solution will be the intervals where the function is greater than or equal to zero.
eleventhxhour
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Solve the following inequality:

6e) $(x - 3)(x + 1) + (x - 3)(x + 2) \ge 0$

So, I created an interval table with the zeros x-3, x+1, x-3 and x+2 but I keep getting the wrong answer. Could someone help? (this is grade 12 math - so please don't be too complicated).

Thanks.
 
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I would start with factoring the LHS:
$$(x-3)[(x+1)+(x+2)] \geq 0$$
$$\Leftrightarrow (x-3)(2x+3) \geq 0$$

Now create an interval table and look where the function $f(x)=(x-3)(2x+3)$ which has two zeros at $x=3$ and $x=\frac{-3}{2}$ is positive. That will give you the answer.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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