Solving Polynomial Inequalities

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SUMMARY

The discussion focuses on solving the polynomial inequality $(x - 3)(x + 1) + (x - 3)(x + 2) \ge 0$. The correct approach involves factoring the left-hand side to $(x-3)(2x+3) \geq 0$. The zeros of the function are identified as $x=3$ and $x=-\frac{3}{2}$. An interval table is then used to determine where the function is positive, leading to the solution of the inequality.

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  • Understanding of polynomial functions and inequalities
  • Knowledge of factoring techniques in algebra
  • Familiarity with interval testing methods
  • Basic skills in identifying zeros of functions
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  • Practice solving polynomial inequalities using interval tables
  • Learn advanced factoring techniques for higher-degree polynomials
  • Explore the concept of critical points and their significance in inequalities
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eleventhxhour
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Solve the following inequality:

6e) $(x - 3)(x + 1) + (x - 3)(x + 2) \ge 0$

So, I created an interval table with the zeros x-3, x+1, x-3 and x+2 but I keep getting the wrong answer. Could someone help? (this is grade 12 math - so please don't be too complicated).

Thanks.
 
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I would start with factoring the LHS:
$$(x-3)[(x+1)+(x+2)] \geq 0$$
$$\Leftrightarrow (x-3)(2x+3) \geq 0$$

Now create an interval table and look where the function $f(x)=(x-3)(2x+3)$ which has two zeros at $x=3$ and $x=\frac{-3}{2}$ is positive. That will give you the answer.
 

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