Solving Problems: Rates of Change and Value Adjustments in Math

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Homework Help Overview

The discussion revolves around problems related to rates of change and value adjustments in mathematical expressions, specifically involving a hyperbolic function and a quadratic function.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the calculation of rates of change for the function y=4/x and question why the rates differ between specified intervals. They also discuss how changes in the variable d affect the value of s in the equation s=16d^2, with some participants correcting initial misunderstandings regarding the effects of squaring and dividing.

Discussion Status

Some participants have provided feedback on the correctness of the answers, with ongoing clarification about the implications of squaring the variable. There is a mix of agreement and correction regarding the interpretation of how changes in d affect s, indicating a productive exploration of the concepts involved.

Contextual Notes

Participants are navigating through assumptions about the mathematical properties of the functions involved, particularly regarding the effects of squaring and the implications for value changes. There is a noted lack of consensus on the correct interpretation of the second problem's answer.

GLprincess02
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There are two more problems I am unsure of, so if someone could just check my answers, I'd be grateful.

Problem:
Suppose y=4/x.
a) Find the rate of change from x=1 to x=2
b) Find the rate of change from x=2 to x=3
c) Why are a and b not equal?

Answers:
a) -2
b) -2/3
c) It is a hyperbola

Problem:
Suppose [tex]s=16d^2[/tex]
a) How does the value of s change if d is doubled?
b) How does the value of s change if d is divided by 3?

Answers:
a) s is multiplied by 2
b) s is divided by 3
 
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Problem 1 is correct
Problem 2 is incorrect. just look at d = 1. Since it is a squared term it would be multiplied by 4. And if it is divided by 3 S is (1/3)^2 = 1/9 S.
 
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Oh ok, I disregarded the square part. And you would still divide by 1/9 in part b, right? So the answer would be "s is divided by 1/9?"
 
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For your answer in (b) it would be divided by 9. Again this is because we have a squared term. If [tex]s = 16d[/tex] then it would be divided by 3 because of the linear term. And s would also be multiplied by 2 if we had the linear term.
 
no S would be divided by 9
 
Sorry, I hadn't read your second post before I edited mine.
And I get it it now. Thank you for your help!
 
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Cool! But I'm confused...how do you know I like it?
 
Lol ok that makes sense! I use pretty much the same username for every site I'm on. Is courtigrad your name on youtube, too?
 

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