Solving Q1 of MathIII Paper60: Ricci Identity & Killing Vectors

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Homework Help Overview

The discussion revolves around a problem from a mathematics paper concerning Ricci identities and Killing vectors in the context of differential geometry. The original poster attempts to demonstrate a specific identity involving the covariant derivative of a Killing vector and the Riemann curvature tensor.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the manipulation of the Ricci identity and the properties of Killing vectors. The original poster expresses difficulty in reaching the final form of the identity and seeks clarification on the implications of certain tensor equations. Others suggest starting points based on Ricci's identity and question the notation used in the discussion.

Discussion Status

The discussion is ongoing, with participants exploring various approaches to the problem. Some guidance has been offered regarding the use of Ricci's identity, but there is no explicit consensus on the final steps or the relevance of certain properties to the original question.

Contextual Notes

There is a mention of assumptions regarding the absence of torsion and the implications of the Killing vector properties. The original poster also raises questions about the conditions under which Killing vectors vanish and the maximum number of linearly independent Killing vectors in a given spacetime dimension.

latentcorpse
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Hi I'm trying Q1 of this paper:
http://www.maths.cam.ac.uk/postgrad/mathiii/pastpapers/2005/Paper60.pdf
and have got to the bit where I need to show that \xi_{b;ca}=-R_{bca}{}^d \xi_d

Now I know that R_{bca}{}^d \xi_d=R_{bcad} \xi^d = R_{adbc} \xi^d = \nabla_b \nabla_c \xi_a - \nabla_c \nabla_b \xi_a

where I got that last equality by rearranging the Ricci identity \nabla_c \nabla_d Z^a - \nabla_d \nabla_c Z^a = R^a{}_{bcd}Z^b

So then we have -R_{bca}{}^d \xi_d = \nabla_c \nabla_b \xi_a - \nabla_b \nabla_c \xi_a = -\nabla_c \nabla_a \xi_b + \nabla_b \nabla_a \xi_c
where I used the Killing property on the first term to get a \xi_b term like we are looking for but I can't quite manipulate it into the final answer. Can anybody see what I am doing wrong?And then in the last bit, can somebody help me to show that if the Killing vector and the first derivative vanish at a point then they vanish everywhere?

And what about the final part about how many linearly independent Killing vectors can there be? My notes say that a n dimensional spacetime is maximally symmetric if there exist \frac{n(n+1)}{2} linearly independent Killing vectors. But I don't actually know whether this is relevant to the question at hand or not?

Thanks.
 
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I would start with

R_{[ij|k]l} = 0

from which you get based on Ricci's identity in the absence of torsion

\nabla_{[k}\nabla_{j}\xi_{i]} = 0

from which you should get by expansion into the 6 possible terms and regrouping based on

\nabla_{(i}\xi_{j)} = 0

an expression showing you the right way to get the final identity.
 
dextercioby said:
I would start with

R_{[ij|k]l} = 0

from which you get based on Ricci's identity in the absence of torsion

\nabla_{[k}\nabla_{j}\xi_{i]} = 0

from which you should get by expansion into the 6 possible terms and regrouping based on

\nabla_{(i}\xi_{j)} = 0

an expression showing you the right way to get the final identity.

Thanks for your reply. What do you mean by R_{[ij|k]l} = 0? Is there supposed to be another vertical line in there somewhere to indicate one of the indices is not antisymmetrised?
 
No, sorry, the vertical line comes from the Youg tableau. So disregard it. I put it there from discussions on such tensors outside GR that have not left my mind yet.
 

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