Solving Refraction: Critical Angle & Min. Angle of Incidence

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SUMMARY

The discussion focuses on calculating the critical angle and minimum angle of incidence for light traveling from ice (refractive index 1.3) to air. The critical angle, calculated using the formula sin(θc) = 1/n, results in θc = 50.3 degrees. For the minimum angle of incidence required for light to refract out of the ice block, participants suggest drawing a diagram to clarify the problem. The consensus is that the minimum angle does not need to be applicable at every point along the surface, but rather at some point.

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Homework Statement


Light traveling thorugh air is at incident at point x on the block of ice. If the refractive index is 1.3, calculate
a) the critical angle at the ice-air interface (3 marks)
b) the minimum angle of incidence, for the light to Y refracted out of the block at any point along the top surface (7 marks)

Homework Equations

The Attempt at a Solution


a) sin(θc)=1/nm
θ= sin-1(1/1.3)
θ= 50.3 (1 d.p)

is this right?

b) Need help on this one
 
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(a) is right.

For (b) there's a diagram to accompany it?
 
NascentOxygen said:
(a) is right.

For (b) there's a diagram to accompany it?

yep it is in the file i uploaded
 

Attachments

thank you for helping btw :)
 
I can view only jpegs, sorry.
 
NascentOxygen said:
I can view only jpegs, sorry.
Managed to turn it into jpeg
 

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I was anticipating there'd be a point Y. I find there is not.

Perhaps you meant to type
b) the minimum angle of incidence, for light to be refracted out of the block at any point along the top surface[/color]?

If so, start by drawing a large diagram with all straight lines (e.g., by using a ruler).

By "any point" I think they don't mean "every point", just at least some point.
 

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