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## Homework Statement

When the incidence angle is equal to the angle of refraction?

## Homework Equations

sina/sinb=n2/n1

## The Attempt at a Solution

I think as a=b => sina=sinb => n1=n2. We should have the same environment? But is that refraction?

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- Thread starter zade70
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In summary, at the interface of two different media, there is a certain angle of incidence where the incident ray passes straight through. This angle is equal to the critical angle of refraction, which can be found by using Snell's law. When the incidence angle is equal to the angle of refraction, the refractive indices of the two media are equal.

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When the incidence angle is equal to the angle of refraction?

sina/sinb=n2/n1

I think as a=b => sina=sinb => n1=n2. We should have the same environment? But is that refraction?

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when b= pi/2 rad. It is the limit angle for a. sina=n2/n1blue_leaf77 said:certainangle of incidence where the incident ray just passes straight through. What is this angle?

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No, that corresponds to critical angle refraction. It very simple, you have Snell's law ##n_1 \sin a = n_2 \sin b##. Try to find azade70 said:when b= pi/2 rad. It is the limit angle for a. sina=n2/n1

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a=b=0 rad? 0=0blue_leaf77 said:No, that corresponds to critical angle refraction. It very simple, you have Snell's law ##n_1 \sin a = n_2 \sin b##. Try to find atrivialangle ##a=b## which will make the left and right hand side of Snell's law equal irrespective of the refractive indices.

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Yes.

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