Solving SI Unit Analysis: Force & Area

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The discussion focuses on solving unit analysis problems related to force and area, specifically regarding the drag force equation Fdrag = CAv². Participants clarify that the constant C's units can be derived by rearranging the equation to C = F/(Av²) and substituting the appropriate units for force and area. The confusion arises from understanding the steps in dimensional analysis, which ensures that units on both sides of an equation match. It is emphasized that rearranging equations is crucial for solving these types of problems. Overall, the conversation highlights the importance of systematic approaches in unit analysis for physics problems.
Nirupt
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Homework Statement



When an object falls through air, there is a drag force that depends on the product of the surface area, A (m2), and the square of the velocity, in (m/s). The equation is Fdrag = CAv2. The metric unit of force is the Newton, or (N). 1 N = 1 kg*m/s2. What are the units of the constant C?

and

Given the equation F =kA, where F is a force, k is a constant, and A is area, use unit analysis to determine the units of k.

Homework Equations





The Attempt at a Solution



Answer choices for the first:

m*s2/N

m*s2/N4

N*s2/m4

N*s/m2

Answer choices for the second:

N*m2, or kg*m3/s2

N/m2, or kg/(m*s2)

m2/N, or m*s2/kg

N*m, or kg*m2/s2

I'm just having trouble starting this class out, and I'm sure this stuff is simple but I'm being thrown off by the steps and my teacher is pretty disorganized but his explanations are confusing me. I would love information and steps on how to solve this.
 
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First step would be to rearrange each of your equations for the quantity you want the units for. What exactly is it you find difficult? Dimensional analysis is used so that the units on both sides of an eqn check out. (I.e think of it like 'you can only equate a vector with a vector'. Similarly, a force can only equal a force, etc.. so units on left = units on right)
 
Just rearrange the equation: F = CAv2; C = F/(Av2).
Then substitute for F etc. using the units as though they were algebraic variables:
C = (kg m s-2)/(m2 (m/s)2)
and simplify.
 
Wow.. for some reason I was forgetting to rearrange the equation which is the first step.. lol sorry I was just over thinking it.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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