Solving Sine Waves Problem: Find Time for π Radians

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The discussion centers on calculating the time it takes for a sine wave with a frequency of 10Hz and an amplitude of 5 units to reach a phase of π radians. The equation used is y(t) = A . sin(2.π.f.t + φ). A user initially calculated the time as 0.038 seconds, but expected the answer to be 0.005 seconds. The discrepancy in the results suggests a potential error in the phase calculation or the application of the sine function. Clarification on the correct approach is sought to resolve the confusion.
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A sine wave with a frequency of 10Hz and an amplitude of 5 units phases from zero to 2π radians in a complete cycle. How long does it take for the phase to reach a value of π radians?

y(t) = A . sin (2.π.f.t + φ)

0.1 = 5 x sin (2x∏x10x time + 3.14)

time = 0.038 seconds

But the answer suppose to be 0.005 and I got 0.038.

Thank you!
 
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