Solving Sound Wave Question: Energy Delivered to Eardrum

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Homework Help Overview

The problem involves calculating the energy delivered to the eardrum from a sound wave, given the intensity of the sound and the dimensions of the eardrum. The subject area pertains to acoustics and wave physics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of the intensity equation and the importance of correctly calculating the radius of the eardrum. There are attempts to clarify the calculation process and the assumptions regarding the geometry of the eardrum.

Discussion Status

The discussion is ongoing, with some participants providing guidance on the correct approach to the problem, while others express confusion about their calculations. There is no explicit consensus on the final answer yet.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can share or the methods they can use. There is also a note about keeping personal messages out of the public thread.

stuti911
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Homework Statement



Sound is detected when a sound wave causes the eardrum to vibrate. Typically, the diameter of the eardrum is about 8.4mm in humans. When someone speaks to you in a normal tone of voice, the sound intensity at your ear is approximately 1 * 10^-6 W/m^2. How much energy is delivered to your eardrum each second?

Homework Equations



I = P/(4pi*r^2)

The Attempt at a Solution



I tried using the equation and I got 2.20×10^−10 W as my answer, but it is wrong. I cannot understand why, because the question seems really simple.
Any help is appreciated, thanks!
 
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stuti911 said:
I tried using the equation and I got 2.20×10^−10 W as my answer, but it is wrong. I cannot understand why, because the question seems really simple.
Any help is appreciated, thanks!
The diameter of the eardrum is about 8.4 mm. Which means the radius is half that. :wink:

[Edit: And welcome to Physics Forums!]
 
Last edited:
yes, so if you take proper radius you will get the answer.
 
yes, i did take the radius
this is my calculation:
(10^-6)*(0.00001764*4*pi) which gives my the answer above
can any of you try the question?
thanks!
 
isn't the answer 5.54*10^(-11)W ?
 
first of all, take eardrum as a circle, not sphere, and so use area as pi*r^2
 
allright.. i got it!
thanks a whole bunch :)
 
welcome Stuti...would you accept my friend request?
 
supratim1 said:
welcome Stuti...would you accept my friend request?

Please keep personal messages out of public threads
 

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