Intensity of sound wave and energy

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SUMMARY

The discussion focuses on calculating the energy transferred to an eardrum from a sound wave with an intensity of 2x10^(-3) W/m^2 over a duration of 1 minute. The area of the eardrum, calculated using its diameter of 6.0 mm, is crucial for determining the power using the formula P=IA. The initial calculation yielded a power of 2.2610x10^-7 W, leading to an energy transfer of 1.3572x10^-5 J. However, the accuracy of the area calculation was questioned, indicating a need for verification.

PREREQUISITES
  • Understanding of sound wave intensity and its measurement
  • Familiarity with the formula P=IA (Power = Intensity x Area)
  • Knowledge of area calculation for circular surfaces
  • Basic principles of energy transfer in physics
NEXT STEPS
  • Review the calculation of the area of a circle using the formula A=πr²
  • Explore the relationship between sound intensity and perceived loudness
  • Investigate the effects of sound wave energy on human hearing
  • Learn about the units of power and energy in the context of acoustics
USEFUL FOR

Students studying physics, particularly those focusing on acoustics and energy transfer, as well as educators seeking to clarify concepts related to sound intensity and its effects on human physiology.

Pambos
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Homework Statement



A sound wave with intensity 2x10^(-3) W/m^2 is perceived to be modestly loud. Your eardrum is 6.0 mm in diameter. How much energy will be transferred to your eardrum while listening to this sound for 1.0 min?

Homework Equations


P=IA=(intensity)(area)
=2x10^(-3) * (pi (6x10^-3)^2)
=2.2610x10^-7 W

The Attempt at a Solution


P=IA=(intensity)(area)
=2x10^(-3) * (pi (6x10^-3)^2)
=2.2610x10^-7 W

P=delta E/ delta t
=2.2610x10^-7 J/s * 60 s
=1.3572x10^-5 J

..its not the correct answer can anyone help?
 
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Hi Pambos, Welcome to Physics Forums!

Check your area calculation.
 

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