Solving Static Equilibrium: Find D for Tension of 1200 N

[G-reg]

Homework Statement

In the figure below, a uniform beam of weight 520 N and length 3.4 m is suspended horizontally. On the left it is hinged to a wall; on the right is it supported by a cable bolted to the wall at distance D above the beam. The least tension that will snap the cable is 1200 N.

What value of D corresponds to that tension?

Homework Equations

\SigmaF in the x direction = 1200

The Attempt at a Solution

That equation is a guess within itself..I really have no clue how I should go about solving this problem..

 

[ideasrule]

The beam is in static equilibrium; it's not moving and not accelerating. Because of that, the sum of the forces be in the x and y directions must be 0.

That said, I don't think using forces is the best way to approach this problem. Try using torque: because the beam is not rotating, torque must be zero about any reference frame.

 

[G-reg]

Oh ok so I would set it up like this,

\Sigma\tau = 3.0meters(mg) + ?

The question marks meaning that I don't know what to put after that first 3meters multiplied by mass times gravity.

Thank you for your help!