Solving Statistics Problem: Proving at Least 2 People with Same Hair Count

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SUMMARY

The discussion centers on a statistical problem involving a city of 10 million people, each with an average of 110,000 hairs. The problem requires proving that at least two individuals must have the same hair count. The solution is derived from the Pigeonhole Principle, which states that if there are more items than containers, at least one container must hold more than one item. Given that the maximum possible distinct hair counts (110,001) are far fewer than the population, the conclusion is that at least two people must share the same hair count.

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Homework Statement



There is a city with 10 million people and an average human has 110 000 hairs. Prove that there is at least 2 people with the same amount of hair.

The Attempt at a Solution



I really have no idea of how to even start solving this problem. Sorry.

Also, sorry for the bad english.
 
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Taturana said:

Homework Statement



There is a city with 10 million people and an average human has 110 000 hairs. Prove that there is at least 2 people with the same amount of hair.

The Attempt at a Solution



I really have no idea of how to even start solving this problem. Sorry.

Also, sorry for the bad english.

Is it possible to have 10 million people, all of whom have different numbers of hairs?

RGV
 

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