Solving Stick Thrown in Air with Initial Condition

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Homework Statement



A student throws a stick of length L up into the air.At the moment it leaves her hand the speed of stick's closest end is zero.The stick completes N turns just as it is caught by student at initial release point.What is the height 'h' that center of mass rise ?

Homework Equations



v=ωr

The Attempt at a Solution



I think I can proceed with the problem but feel a little unsure about the initial orientation of the stick just as it leaves the hand and the initial condition that the the speed of stick's closest end is zero .

Could somebody reflect on how to interpret the initial condition given in the problem ?

Thanks
 
I would think that if the centre of mass was to go up, the only way that the point nearest the hand could be moving relative to it would be downwards in order for it to be stationary. I.e. Not left or right.
 
Do you mean the stick is horizontal at the instant it leaves the hand ?
 
See figure.

ehild
 
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  • Diagram of a thin cyan rod lying horizontally with a small orange-tipped end, a curved arrow above it, a straight upward arrow at its centre, and a rod standing vertically with a curved arrow indicating rotation, both marked with a pivot cross.
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Hi ehild...

Someone has rightly said "A picture is worth a thousand words " .

Thanks...