Solving Submarine Problem - Alex

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To solve the submarine problem, start by determining the speed of sound in water, which is affected by temperature and pressure. The echo return time of 5.6 seconds indicates that the sound travels to the ship and back, so calculate the total distance traveled. Divide this distance by two to find the direct distance to the ship. While temperature and salinity can impact sound speed, using standard values for seawater is often sufficient for basic calculations. Incorporating these factors will enhance the accuracy of your solution.
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Hi,

I need to solve this problem but I have no idea where to start. I made a little drawing with all the informations I have but now I'm stuck. Here's the problem:

A submarine uses sonar waves, to identify other ships, by directing a highly directional acoustic pulse at a target, and computing the time duration between the transmission of the "ping", and the return of the echo. If a sub is a depth of 500m and receives a ping return in 5.6s, determine the direct distance to the ship.

I'm not looking for the answer, just a little hint of what to start with. Thanks a lot !

- alex.
 
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What's the speed of sound in water? How far must the sound have traveled in 5.6s? (Don't forget that the sound makes a round trip.)
 
Great ! Thanks. One last question, does the temperature affects anything ? Thanks !
 
Both pressure and temperature will affect the speed of sound. (But I'll bet you can ignore such complications.)
 
The problem actually include the temperature, so I guess I need to include it in my formula. I google'd for it but could only find tables. If density of water is 1, what formula should I use ?

Thanks !
 
Unless this problem is meant to exercise your detailed understanding of the speed of sound in a liquid (the speed depends on the bulk modulus and density, which in turn depend on pressure and temperature), I would just look up the speed of sound (in seawater... salinity counts!) at some standard temperature. That should be good enough.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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