- 7,201
- 527
Yes, except watch plus and minus signs.anglum said:and the vertical force on it is
sin10(73.004) + W + T3sin43 = 0
?
The forum discussion focuses on solving for the tension T1 in a physics problem involving forces at a knot. The user initially calculated T1 using the equation sin(55°) = 90/T1, resulting in an incorrect value of 11.211 kg. Participants emphasized the importance of applying Newton's first law in both x and y directions to establish two equations: T1sin(55°) - T2sin(10°) = 90N and T1cos(55°) - T2cos(10°) = 0. After correcting the calculations, the user determined T1 to be approximately 125.35 N and subsequently calculated T2 and the weight W.
PREREQUISITESStudents and professionals in physics, engineering, and mechanics who are solving tension problems and analyzing forces in static systems.
Yes, except watch plus and minus signs.anglum said:and the vertical force on it is
sin10(73.004) + W + T3sin43 = 0
?
anglum said:so i solve for T3 in the horizontal and get 98.303N
then plug that into the vertical and get W = 92.3971N or 9.428275kg
are those the answers you got?
anglum said:for W did u use the equation
sin10(73.007) + T3sin43 - W = 0
12.677 + (98.303)(.681998) - W = 0
12.677 + 67.042 = W
W = 79.719484 N or 8.13464 kg?