Solving Tension Problem: Can't Find T1

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Homework Help Overview

The discussion revolves around a tension problem involving multiple forces acting on knots, specifically focusing on the calculation of T1 and T2. The context includes the application of trigonometric relationships and Newton's laws to analyze the forces in both vertical and horizontal directions.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the use of trigonometric functions to relate tension forces to known vertical and horizontal forces. There are attempts to set up equations based on the equilibrium of forces at the knots, with some questioning the conversion of tension from Newtons to kilograms.

Discussion Status

Participants are actively engaging with the problem, discussing various equations and attempting to clarify their setups. Some have provided guidance on isolating variables and checking signs in their equations, while others express uncertainty about their calculations and the correctness of their approaches.

Contextual Notes

There is mention of a diagram that is referenced but not visible in the discussion. Participants are also navigating the constraints of homework requirements, including specific units for tension.

  • #31
anglum said:
and the vertical force on it is

sin10(73.004) + W + T3sin43 = 0

?
Yes, except watch plus and minus signs.
 
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  • #32
how should the plus minus signs be? and isn't the angle 43? for horizontal and vertical
 
  • #33
ok I am assuming this is what they should look like

cos10(73.004) - T3cos43 = 0 HORIZONTAL

sin10(73.007) + T3sin43 - W = 0 VERTICAL

did i fix them
 
  • #34
Yeah, those look right.
 
  • #35
so i solve for T3 in the horizontal and get 98.303N

then plug that into the vertical and get W = 92.3971N or 9.428275kg

are those the answers you got?
 
  • #36
anglum said:
so i solve for T3 in the horizontal and get 98.303N

then plug that into the vertical and get W = 92.3971N or 9.428275kg

are those the answers you got?

I get something different for W. But I get the same T3.
 
  • #37
for W did u use the equation

sin10(73.007) + T3sin43 - W = 0

12.677 + (98.303)(.681998) - W = 0

12.677 + 67.042 = W

W = 79.719484 N or 8.13464 kg?
 
  • #38
anglum said:
for W did u use the equation

sin10(73.007) + T3sin43 - W = 0

12.677 + (98.303)(.681998) - W = 0

12.677 + 67.042 = W

W = 79.719484 N or 8.13464 kg?

yeah that looks right.
 
  • #39
thanks again
 

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