Solving Tension Problem: Can't Find T1

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SUMMARY

The forum discussion focuses on solving for the tension T1 in a physics problem involving forces at a knot. The user initially calculated T1 using the equation sin(55°) = 90/T1, resulting in an incorrect value of 11.211 kg. Participants emphasized the importance of applying Newton's first law in both x and y directions to establish two equations: T1sin(55°) - T2sin(10°) = 90N and T1cos(55°) - T2cos(10°) = 0. After correcting the calculations, the user determined T1 to be approximately 125.35 N and subsequently calculated T2 and the weight W.

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  • #31
anglum said:
and the vertical force on it is

sin10(73.004) + W + T3sin43 = 0

?
Yes, except watch plus and minus signs.
 
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  • #32
how should the plus minus signs be? and isn't the angle 43? for horizontal and vertical
 
  • #33
ok I am assuming this is what they should look like

cos10(73.004) - T3cos43 = 0 HORIZONTAL

sin10(73.007) + T3sin43 - W = 0 VERTICAL

did i fix them
 
  • #34
Yeah, those look right.
 
  • #35
so i solve for T3 in the horizontal and get 98.303N

then plug that into the vertical and get W = 92.3971N or 9.428275kg

are those the answers you got?
 
  • #36
anglum said:
so i solve for T3 in the horizontal and get 98.303N

then plug that into the vertical and get W = 92.3971N or 9.428275kg

are those the answers you got?

I get something different for W. But I get the same T3.
 
  • #37
for W did u use the equation

sin10(73.007) + T3sin43 - W = 0

12.677 + (98.303)(.681998) - W = 0

12.677 + 67.042 = W

W = 79.719484 N or 8.13464 kg?
 
  • #38
anglum said:
for W did u use the equation

sin10(73.007) + T3sin43 - W = 0

12.677 + (98.303)(.681998) - W = 0

12.677 + 67.042 = W

W = 79.719484 N or 8.13464 kg?

yeah that looks right.
 
  • #39
thanks again
 

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