Solving the Einstein Gravity Tensor for the Newton Potential

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The discussion focuses on solving the Einstein gravity tensor's Lagrangian density to derive the Newton potential. The equations of motion simplify to a form that allows for the calculation of the field h in response to a point source T. The participant derives h as proportional to the mass m and inversely proportional to the distance r, indicating a potential solution. However, confusion arises regarding the value of the exponent b, which is critical for matching the classical Newtonian potential. The participant seeks clarification on dimensional analysis to resolve discrepancies in the calculations, particularly regarding the factor of 2 in the exponent.
Malamala
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Homework Statement


The Lagrangian density for the ##h=h^{00}## term of the Einstein gravity tensor can be simplified to: $$L=-\frac{1}{2}h\Box h + (M_p)^ah^2\Box h - (M_p)^b h T$$ The equations of motion following from this Lagrangian looks roughly like (I didn't calculate this, they are given in the problem): $$\Box h = (M_p)^{a}\Box(h^2)-(M_p)^bT$$ For a point source ##T=m\delta^3(x)##, solve the equation for h to first order in the source T, with ##M_p=\frac{1}{\sqrt{G_N}}##. This result should reproduce the Newtonian potential.

Homework Equations

The Attempt at a Solution


So to first order, we can drop the ##h^2## term and we are left with $$\Box h = -(M_p)^bT $$ $$h = \frac{1}{\Box} (-(M_p)^bT)=-(M_p)^b\frac{1}{\Box} (T)$$ where ##\frac{1}{\Box}## is the propagator (Green function) associated with the field. Based on some calculations and properties of the Green function I got $$h=-\frac{M_p^b m }{4 \pi r}$$ I am pretty confident of my calculations so far. Now, to actually get Newton potential I need ##M_p^b=4\pi G##. It is not mentioned, but I assume ##G_N=4\pi G## so the only thing I have to show is that ##b=-2## to reproduce the classical result. I just don't get that value... I tried to do a dimensional analysis of the Lagrangian, and I have ##[L]=4##, ##[\Box] = 2## so ##[h]=1##. As T is the stress energy tensor ##[T]=4## and ##[M_p]=1## so we are left with ##b=-1## I just don't know where I am missing a factor of 2. Also, assuming my calculations above were wrong, the whole time ##(M_p)^b## was just a constant so that should be the same, regardless of the rest of the solution. So I guess I am doing something wrong with the dimensional analysis. Can someone help me please? Thank you!
 
Physics news on Phys.org
Assuming that ##h_{\mu\nu}## is the weak field correction to the Minkowski metric, it is dimensionless. The Einstein-Hilbert action is not always written on dimensionless form, but the appropriate factors of ##M_P## are then included as an overall factor when icluding matter fields.
 

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