Solving the Einstein Gravity Tensor for the Newton Potential

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SUMMARY

The discussion focuses on solving the Einstein gravity tensor for the Newton potential using a simplified Lagrangian density: $$L=-\frac{1}{2}h\Box h + (M_p)^ah^2\Box h - (M_p)^b h T$$. The equations of motion derived from this Lagrangian yield $$\Box h = (M_p)^{a}\Box(h^2)-(M_p)^bT$$. The participant successfully derived the expression for the gravitational potential as $$h=-\frac{M_p^b m }{4 \pi r}$$ and concluded that to reproduce the Newtonian potential, it is necessary to establish that $$M_p^b=4\pi G$$, leading to the requirement that $$b=-2$$. The participant expressed confusion regarding the dimensional analysis that suggested $$b=-1$$ instead.

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  • Understanding of Lagrangian mechanics in the context of general relativity
  • Familiarity with the Einstein gravity tensor and its implications
  • Knowledge of Green's functions and their role in field theory
  • Basic principles of dimensional analysis in theoretical physics
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  • Learn about the properties of Green's functions in the context of field equations
  • Explore dimensional analysis techniques specific to gravitational theories
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The discussion is beneficial for theoretical physicists, graduate students in physics, and researchers focusing on general relativity and gravitational theories, particularly those interested in the mathematical foundations of gravitational potentials.

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Homework Statement


The Lagrangian density for the ##h=h^{00}## term of the Einstein gravity tensor can be simplified to: $$L=-\frac{1}{2}h\Box h + (M_p)^ah^2\Box h - (M_p)^b h T$$ The equations of motion following from this Lagrangian looks roughly like (I didn't calculate this, they are given in the problem): $$\Box h = (M_p)^{a}\Box(h^2)-(M_p)^bT$$ For a point source ##T=m\delta^3(x)##, solve the equation for h to first order in the source T, with ##M_p=\frac{1}{\sqrt{G_N}}##. This result should reproduce the Newtonian potential.

Homework Equations

The Attempt at a Solution


So to first order, we can drop the ##h^2## term and we are left with $$\Box h = -(M_p)^bT $$ $$h = \frac{1}{\Box} (-(M_p)^bT)=-(M_p)^b\frac{1}{\Box} (T)$$ where ##\frac{1}{\Box}## is the propagator (Green function) associated with the field. Based on some calculations and properties of the Green function I got $$h=-\frac{M_p^b m }{4 \pi r}$$ I am pretty confident of my calculations so far. Now, to actually get Newton potential I need ##M_p^b=4\pi G##. It is not mentioned, but I assume ##G_N=4\pi G## so the only thing I have to show is that ##b=-2## to reproduce the classical result. I just don't get that value... I tried to do a dimensional analysis of the Lagrangian, and I have ##[L]=4##, ##[\Box] = 2## so ##[h]=1##. As T is the stress energy tensor ##[T]=4## and ##[M_p]=1## so we are left with ##b=-1## I just don't know where I am missing a factor of 2. Also, assuming my calculations above were wrong, the whole time ##(M_p)^b## was just a constant so that should be the same, regardless of the rest of the solution. So I guess I am doing something wrong with the dimensional analysis. Can someone help me please? Thank you!
 
Physics news on Phys.org
Assuming that ##h_{\mu\nu}## is the weak field correction to the Minkowski metric, it is dimensionless. The Einstein-Hilbert action is not always written on dimensionless form, but the appropriate factors of ##M_P## are then included as an overall factor when icluding matter fields.
 

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