Solving the Energy Conservation Equation for Flywheel & Mass

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The discussion focuses on solving the energy conservation equation for a flywheel system involving a 2kg mass and a flywheel with a radius of 120mm. The relationship between the distance fallen (h) and the linear velocity (v) of the mass is established by the equation h = v²(0.051 + 1.77I), where I represents the moment of inertia. Participants emphasize the importance of understanding the moment of inertia and the energy associated with a rotating mass to derive the correct relationship.

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1. A flywheel about a string is wrapped. At the end of the string is a mass, 2kg, which is initially held staionary at the datum position. If the mass is released it will fall causing the flywheel to rotate, and after the mass has fallen a distance of h meters it has a linear velocity of v m/s whislt the flywheel the flywheel has a rotational velocity of W rad/s

The mass of the object is 2Kg, and the radius of the flywheel is 120mm. By using the principle of conservation of energy, show that the distance fallen, h, and the velocity, v, of the mass and the distance are related by the equation: h=v2(0.051+1.77I)




2. h=v2(0.051+1.77I)



3. I have made several attempts at this but I can't seem to find a relationship with the equation, is it the equation or is it just me?
 
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Are you familiar with the Moment of Inertia, and what the energy is for a rotating mass?
 

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