Solving the Geodesic Equation: Raising Contravariant Indices

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Homework Help Overview

The discussion revolves around manipulating the geodesic equation, specifically focusing on raising contravariant indices in the context of the equation's non-affine form. Participants are exploring the mathematical properties of the geodesic equation and the implications of tensor transformations.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand how to raise contravariant indices in the geodesic equation. Some participants provide insights into the manipulation of indices and the properties of covariant derivatives, while others question the validity of specific forms presented.

Discussion Status

The discussion is active, with participants offering clarifications and exploring different interpretations of the geodesic equation. There is a constructive exchange of ideas regarding the manipulation of indices and the nature of covariant derivatives, though no consensus has been reached on the original poster's proposed form.

Contextual Notes

Participants are working within the constraints of the geodesic equation and its non-affine form, with an emphasis on maintaining the mathematical integrity of tensor operations. The discussion reflects a focus on understanding the underlying principles rather than arriving at a definitive solution.

Pacopag
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Homework Statement


I would like to manipulate the geodesic equation.


Homework Equations


The geodesic equation is usually written as
k^{a}{}_{;b} k^{b}=\kappa k^{a} (it is important for my purpose to keep it in non-affine form).
It is clear that by contracting with the metric we may write alternatively
k_{a ;b} k^{b} = \kappa k_{a}.
What I would like to know is how to raise to a contravariant indices in the derivative on the left-hand side.

The Attempt at a Solution


If I had to guess, I would like to be able to write something like.
k^{a ;b} k_{b}=\kappa k^{a}.
Is this a valid form of the geodesic equation?
 
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Sure. g^{a b} k_{;b}=k^{;a}.
 
Thank you for your reply Dick.
But how do you explain the lowering of the b index in the second factor on the left-hand side?
 
On the LHS you've got {k^a}_{;b}k^b=k^{a;c}g_{cb}k^b=k^{a;c}k_c=k^{a;b}k_b
 
Excellent! Thank you both very much.
 
Pacopag said:
Excellent! Thank you both very much.

The crucial point is that the covariant derivative transforms as a tensor, unlike say, the partial derivative.
 

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