Solving the Kinetic Energy of a Baseball

[blayman5]

Homework Statement

An outfielder throws a 2.01 kg baseball at a
speed of 108 m/s and an initial angle of 11.9◦.
What is the kinetic energy of the ball at the
highest point of its motion? Answer in units
of J.

Homework Equations

change KE=W
R=Vi^2/g (sin2O)
V^2=Vi^2+2ax
F=ma
W=Fx

The Attempt at a Solution

Found the range
Plugged it into galileo's formula to find the acceleration
found the force F=ma
multipled by range
Did I go about this correctly?

 

[LowlyPion]

Homework Statement

An outfielder throws a 2.01 kg baseball at a
speed of 108 m/s and an initial angle of 11.9◦.
What is the kinetic energy of the ball at the
highest point of its motion? Answer in units
of J.

Homework Equations

change KE=W
R=Vi^2/g (sin2O)
V^2=Vi^2+2ax
F=ma
W=Fx

The Attempt at a Solution

Found the range
Plugged it into galileo's formula to find the acceleration
found the force F=ma
multipled by range
Did I go about this correctly?

What they are basically asking for is what is the KE at max height.

When the ball's flight is maximum, then all the vertical velocity is stored in potential energy. That leaves only the horizontal component of velocity needed to figure its mV²/2

 

[blayman5]

That means there would be no kinetic energy because of the conservation on energy?

 

[blayman5]

vox=vocosO =105.679m/s
KE=mv^2/2
=11,223.9 J

Thanks Lowlypion