Solving the Puzzle: Ball Thrown Upward

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SUMMARY

A ball thrown straight up with an initial speed of 40 m/s reaches a maximum height of 80 meters before descending. The total time the ball remains in the air is 8 seconds, calculated by dividing the initial speed by the acceleration due to gravity (10 m/s²) and multiplying by 2 for the ascent and descent. The correct approach to find the maximum height involves using the kinematic equation for displacement, specifically \( h = v_i t + \frac{1}{2} a t^2 \), where \( v_i \) is the initial velocity, \( a \) is the acceleration, and \( t \) is the time to reach the peak.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of initial velocity and acceleration due to gravity
  • Ability to manipulate algebraic equations
  • Familiarity with the concept of displacement
NEXT STEPS
  • Study the kinematic equation for displacement: \( h = v_i t + \frac{1}{2} a t^2 \)
  • Learn how to calculate maximum height in projectile motion
  • Explore the effects of gravity on vertical motion
  • Practice solving problems involving initial velocity and time of flight
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Students studying physics, educators teaching kinematics, and anyone interested in understanding projectile motion and its calculations.

iluvpandas
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Homework Statement



A ball is thrown straight up with an initial speed of 40 m/s. (Neglect air resistance.)
How high does it go? how long does it stay i the air



Homework Equations



i know the second part is 8 because its basically saying 40m every second divide by acc.(gravity) which is basically 10 and multiply by 2 one second going up and another going down. but I am completely lost on the first part

The Attempt at a Solution



im not sure but i think i use the formula for displacement? but when i tried the answer was wrong.
 
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Write the three motion equations here. And then see what you are looking for.
What is the final velocity?
What is initial velocity?
What is distance? - not known
What is time? - not given
What is acceleration?

You should try equation with time in it when finding the distance.
 

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