Solving the Tension in a String Attached to a 10 kg Block

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SUMMARY

The tension in the string attached to a 10 kg block being pulled horizontally with a force of 50 N, while experiencing a frictional force of 30 N, is calculated to be 80 N. The net force acting on the block is determined by subtracting the frictional force from the applied force, resulting in a tension of 50 N plus the 30 N of friction, leading to a total of 80 N. This calculation is essential for understanding the dynamics of forces acting on objects in motion.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Basic knowledge of forces, including tension and friction
  • Familiarity with free-body diagrams
  • Concept of net force and equilibrium in physics
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  • Study the concept of net force in detail
  • Learn how to draw and analyze free-body diagrams
  • Explore the effects of friction on motion
  • Investigate real-world applications of tension in strings and cables
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JohnD623
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Homework Statement


A string is attached to a 10 kg block that lies on a horizontal surface. If the string is pulled horizontally with a force of 50 N, friction acting against it is 30 N. What is the tension in the string?

Homework Equations


F = ma

The Attempt at a Solution


Would it be 50 N? Friction wouldn't matter. Or does it matter? The answer is 80 N?
 
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Hi JohnD623! http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif
the string is pulled horizontally with a force of 50 N,
End of story!

The tension in the string is the force it carries, 50N.

To take this question further ...
30N overcomes friction, so how to account for the other 20N?
 
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