Solving the Yo-yo Problem: Final Velocity Calculation

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The discussion centers on calculating the final velocity of a yo-yo with a mass of 400 kg and a radius of 1.5 m, released from a height of 57 m. The user initially calculated the acceleration using the formula derived from Newton's second law and rotational dynamics but realized they were mistakenly focusing on acceleration instead of final velocity. After some clarification, it was noted that the user also confused the radius variables, using lowercase 'r' instead of uppercase 'R'. This led to a correction in their approach to solving the problem. Ultimately, the conversation emphasizes the importance of correctly interpreting the problem and using the right variables in calculations.
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Homework Statement



A yo-yo has mass of 400 kg and radius of 1.5m. Its axle of rotation has a radius of 0.1m. Its string is attached to a crane. What is its final velocity after it is released.
mass (m)=400 kg
Radius (R)= 1.5 m
axle of yo-yo (r)= 0.1 m
height (h)=57m
angular acceleration (x)= x

Homework Equations



F=ma; I=(1/2)mr^2; a=xr a/r=x

The Attempt at a Solution



F=ma ; Torque=Tr=Ix T=Ix/r

Fnet,y = mg - T = ma

mg - I(a/r)/r = ma

mg = ma + I(a/r)/r

mg/ (m + I/r^2) = a

mg/(m + (1/2)mr^2/r^2 ) = a

a = 6.53 m/s

This doesn't seem right. Can anyone show me my error?
 
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well you have calculated the accelertion whereas the question asks for final velocity ...
 
lol . ok figured it out. i was also using lowercase r instead of uppercase R.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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