Solving Thin Film Problem: Wavelength in Visible Spectrum

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SUMMARY

The discussion centers on calculating the wavelength of light most strongly transmitted through a thin film of magnesium fluoride (MgF2) with a thickness of 80.0 nm, coated on a camera lens with an index of refraction of 1.80. The correct approach involves using the formula for destructive interference, specifically 2t = m*(lambda/n), where n is the index of refraction of the film. The user initially provided incorrect wavelengths of 116 nm, 160 nm, and 232 nm, but later identified that the index of refraction of MgF2 (n = 1.45) is crucial for determining the correct wavelength in the visible spectrum.

PREREQUISITES
  • Understanding of thin film interference principles
  • Familiarity with the index of refraction and its impact on wavelength
  • Knowledge of the visible spectrum range (approximately 380 nm to 750 nm)
  • Ability to apply the formula for destructive interference in optics
NEXT STEPS
  • Research the calculation of wavelengths in thin films using the formula 2t = m*(lambda/n)
  • Study the properties of magnesium fluoride (MgF2) and its applications in optics
  • Explore the concept of destructive interference in more detail
  • Learn about the visible spectrum and how different wavelengths correspond to colors
USEFUL FOR

Students preparing for exams in optics, optical engineers, and anyone interested in understanding thin film interference and its applications in camera lens design.

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A camera lens (n = 1.80) is coated with a thin film of magnesium fluoride (n = 1.45) of thickness 80.0 nm. What wavelength in the visible spectrum is most strongly transmitted through the film?

I have tried to solve this problem for quite a while now, and i hate to admit that there might be a small thing that i am missing. i have reached the following answers : 116 nm, 160 nm and 232 nm and all of them are wrong. I am using this formula: 2t= m*(lambda). I only have 2 tries left so please help me out. Also include a reason why you reached that answer. I have a final coming up and i would love to learn the propper way to do this. Thank you in advance.
 
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You want destructive interference for reflection at the first surface.
I think this means lambda in the glass=t.
 
...

Thanks for your attempt, but I already figured out the correct way of doing it. The index of refraction of the MgF2 is the key to the answer.
 

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