Solving this Differential Equation using Convolution

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Homework Help Overview

The discussion revolves around solving a differential equation, specifically $$5s(t)-4s''(t)=r(t)$$, using convolution techniques. The original poster presents an expression involving constants $$c_1$$ and $$c_2$$, which are part of the solution function $$s$$ expressed in terms of a convolution with a function $$q$$.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the convolution method for solving the differential equation and discuss the implications of the constants $$c_1$$ and $$c_2$$. There are attempts to manipulate the equation and clarify the definitions of multiplication versus convolution. Questions arise regarding the dimensionality of the constants and the formulation of the problem statement.

Discussion Status

The discussion is ongoing, with participants providing insights and raising questions about the formulation and interpretation of the problem. Some guidance has been offered regarding the convolution approach, but there is no explicit consensus on the interpretation of the constants or the problem's requirements.

Contextual Notes

There are concerns about compliance with forum rules regarding the demonstration of effort, and some participants express confusion about the notation used in the problem statement.

Jack1235
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Homework Statement
The differential equation ##5s(t)-4s''(t)=r(t)## can be solved by the convolution ##s=q*r## where ##q(t)=c_1*\exp(-c_2*|(t)|)##. Find ##c_1+c_2##.
Relevant Equations
$$\int_{-\infty}^{\infty} r(t-u)s(u) \,du$$
$s=c_1*\exp(-c_2*|(t)|)*r(t)$ But how can I solve $c_1+c_2$ ?
 
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Hello Jack,
:welcome:
I am very much afraid your post will be deleted by one of the mentors soon: it doesn't comply with the PF rules and guidelines (there is no posted apparent effort from your side).
Before that: ##\LaTeX## has to be enclosed by double $$ (for displayed math) and double ## for in-line math:

The differential equation $$5s(t)-4s''(t)=r(t)$$ can be solved by the convolution $$s=q*r$$ where $$q(t)=c_1*\exp(-c_2*|(t)|)$$. Find $$c_1+c_2$$

Relevant Equations: $$\left (\int_{-\infty}^{\infty} r(t-u)s(u) \,du\right )$$
$$s=c_1*\exp(-c_2*|(t)|)*r(t)$$ But how can I solve $$c_1+c_2$$ ?

With ## it looks better:

Homework Statement: The differential equation ##5s(t)-4s''(t)=r(t)## can be solved by the convolution ##s=q*r## where ##q(t)=c_1*\exp(-c_2*|(t)|)##. Find ##c_1+c_2##.​
Relevant Equations: ##\int_{-\infty}^{\infty} r(t-u)s(u) \,du##​
##s=c_1*\exp(-c_2*|(t)|)*r(t)## But how can I solve ##c_1+c_2## ?​
##\ ##​
 
So this is my attempt: ##5(q*r)-4(q*r)''=r(t)## and ##5(C_1\exp(-C_2|t|)*r)-4*(C_1*\exp(-C_2*|t|)*r)''=r(t)##
In addition to that: ##(q*r)''=(-i*2*\pi*\widehat{ts}(\nu))'##
 
Last edited:
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BvU said:
I am very much afraid your post will be deleted by one of the mentors soon: it doesn't comply with the PF rules and guidelines (there is no posted apparent effort from your side).
Since the OP has (belatedly) shown some effort, no moderator action has been taken here.
 
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Good. Now, do I have to sort out when a * stands for multiplication and when it means convolution ?

I also find it strange the problem statement asks for ##c_1 + c_2##. It seems to me they have different dimensions and can not be added. Could it be the problem composer means to ask for ##c_1## and ##c_2## ?

Furthermore: the relevant equation does not really look like an equation at all.
I suppose you meant $$s = q*r \ \ \Leftrightarrow \ \ s(t) =\int_0^t q(\tau) r(t-\tau) \, d\tau \ \ ?$$

Could you please also explain what you do in post #3 ?

##\ ##
 
Note: I tweaked the first post to get most of the LaTeX to render.
 
Then post #2 now looks pretty dumb ...:biggrin:
 

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