Solving this integral with u substitution

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Homework Help Overview

The discussion revolves around evaluating the integral ##\displaystyle\int_{0}^{3}\frac{x+3}{\sqrt{x^{2}+1}}dx+5##, with a focus on the use of substitution methods. Participants explore various approaches to tackle the integral, including u-substitution and potential trigonometric substitutions.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the original substitution attempt of ##u=x^{3}+1## and its implications. Questions arise regarding the effectiveness of this substitution and whether further assistance is needed. Some suggest alternative substitutions, including ##u = x^{3/2}##, and discuss the potential for trigonometric methods. Others express confusion about the setup and the need for clarification on the original poster's work.

Discussion Status

The conversation is ongoing, with participants providing feedback on the original poster's attempts and suggesting different approaches. There is a mix of encouragement for the original poster to engage more deeply with the problem and a recognition that multiple methods may be explored. Some participants have noted corrections to the original problem statement, which may influence the direction of the discussion.

Contextual Notes

There is a noted typo in the original problem statement regarding the exponent in the integral, which has been clarified by participants. The discussion also reflects a learning environment where participants are encouraged to show their work and reasoning.

karush
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Homework Statement
u subst
Relevant Equations
u subst
Evaluate ##\displaystyle\int_{0}^{3}\frac{x+3}{\sqrt{x^{3}+1}}dx+5##
W|A returned 11.7101
ok subst is probably just one way to solve this so
##u=x^{3}+1 \quad du= 3x^2##
 
Last edited:
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What did you try? what is w|A?
 
Wolffram Alpha
u subst
 
Last edited:
Please show your work
 
Orodruin said:
Please show your work
I did what I could in the OP
 
You did nothing in the OP apart from just stating a substitution. What does that give you? Where do you get stuck? Please be specific.
 
ok I can't see how this subst would play out
or do I need to go somewhere elae for help
$$u=x^3+1\quad du=3x^2 \quad (u-1)^{1/3}=x$$
this doesn't render
 
Last edited by a moderator:
karush said:
this doesn't render
It does render properly now that I changed your single-$ delimiters to double-$ delimiters. :wink:

karush said:
or do I need to go somewhere elae for help
If you expect us to do your work for you without you showing any effort, then yes. If you are willing to put in some effort, then you will get great help here at PF.
 
I don't think an ordinary substitution by itself will do the trick. Something to try is 1) the substitution ##u = x^{3/2}##, followed by 2) a trig substitution. The first substitution turns the denominator to ##\sqrt{u^2 + 1}##, which suggests a trig substitution. I worked it through part way, but didn't complete my work, so I'm not sure that this will bear fruit.
 
  • #10
berkeman said:
It does render properly now that I changed your single-$ delimiters to double-$ delimiters. :wink:If you expect us to do your work for you without you showing any effort, then yes. If you are willing to put in some effort, then you will get great help here at PF.

sorry there is a typo in the OP it should be ##x^2## not ##x^3##

i have already solved the problem by expansion
 
  • #11
karush said:
sorry there is a typo in the OP it should be ##x^2## not ##x^3##

i have already solved the problem by expansion
So this means that the OP should read:
karush said:
Homework Statement: Evaluate ##\displaystyle\int_{0}^{3}\frac{x+3}{\sqrt{x^{2}+1}}dx+5##

Relevant Equations: u subst

ok subst is probably just one way to solve this so
The indefinite integral, ##\displaystyle \int \frac{x+3}{\sqrt{x^{2}+1}}dx##, does have a closed form solution,

Break that into the sum of integrals: ##\displaystyle \int \frac{x}{\sqrt{x^{2}+1}}dx + 3\int \frac{1}{\sqrt{x^{2}+1}}dx## .

The first can be handled by a relatively simple substitution.

The second can be done with:
1) a trig substitution, the result of which may require knowing ##\int \sec \theta \ d\theta ##.

2) a hyperbolic function substitution .

3) knowledge of the derivative of the inverse hyperbolic sine function.
 
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  • #12
Mahalo every one
 

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