Solving Tough Differential Equations with Parameters: A Step-by-Step Approach

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SUMMARY

This discussion focuses on solving differential equations involving parameters, specifically the equations -1/r(d/dr)(r*tao)=0 and tao=m(-dv/dr)^n. The user initially struggled with integrating tao and applying the product rule, leading to complications with the parameter n. A solution was provided, showing that the first equation simplifies to r*tao=constant, leading to tao=C/r, and subsequently transforming the second equation into a solvable form for dv/dr. The final integration yields dv=(C/m)^(1/n) r^(-1/n)dr.

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juice34
eq#1) -1/r(d/dr)(r*tao)=0
eq#2)tao=m(-dv/dr)^n (n is a parameter)

for v=0 at r=R and v=V and r=kR (k and V are parameters)

I have no idea how to start this or what is the correct way to start.

I initially integrated tao to get dtao/dr=m(-dv/dr)^n-1, but this just complicates things further with the n-1. Next i plugged in tao into the first equation and then used the product rule so -1/r(d/dr)(r*m(-dv/dr)^n)=0 once again i get the n-1 factor. Then i tried taking the derivative of #1 with respect to r to yield -(1*tao)/r=0. Please could someone please guide me in the right steps!
 
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So your equations are:
[tex]-\frac{1}{r}\frac{dr\tau}{dr}= 0[/tex]
and
[tex]\tau= m\left(\frac{dv}{dr}\right)^n[/tex] ?

Well, multiplying by -r, the first equation is just [tex]\frac{d r\tau}{dr}= 0[/tex] so that [itex]r\tau[/itex]= constant and
[tex]\tau= \frac{C}{r}[/tex]
Then the second equation becomes
[tex]\frac{C}{r}= m\left(\frac{dv}{dr}\right)^n[/tex]
so
[tex]\left(\frac{dv}{dr}\right)^n= \frac{C}{mr}[/tex]
[tex]\frac{dv}{dr}= \frac{C^{1/n}}{m^{1/n}r^{1/n}}[/tex]
[tex]dv= \left(\frac{C}{m}\right)^{1/n} r^{-1/n}dr[/tex]
and integrate.
 
Thank you Hallsofivey!:cool:
 

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