Solving Velocity & Acceleration - A Physics Challenge

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wells=mvp
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Hi, I just had a question i had trouble answering, I am sure its an easy one, but i can't get it, (since I am just starting physics):

a bus starts at rest and accelerates at 1.5m/s^2 until it reaches a velocity of 9m/s. The bus continues at this velocity and then decelerates at -2m/s^2 until it comes to a stop 400m from its starting point. How much time did the bus take to cover the 400m? (ans: 50 seconds)

Im using basic velocity and acceleration formulas and I can't get the answer.
 
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wells=mvp said:
Hi, I just had a question i had trouble answering, I am sure its an easy one, but i can't get it, (since I am just starting physics):

a bus starts at rest and accelerates at 1.5m/s^2 until it reaches a velocity of 9m/s. The bus continues at this velocity and then decelerates at -2m/s^2 until it comes to a stop 400m from its starting point. How much time did the bus take to cover the 400m? (ans: 50 seconds)

Im using basic velocity and acceleration formulas and I can't get the answer.

show us how you work the problem. Have you ever used latex?
 
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wells=mvp said:
Hi, I just had a question i had trouble answering, I am sure its an easy one, but i can't get it, (since I am just starting physics):

a bus starts at rest and accelerates at 1.5m/s^2 until it reaches a velocity of 9m/s. The bus continues at this velocity and then decelerates at -2m/s^2 until it comes to a stop 400m from its starting point. How much time did the bus take to cover the 400m? (ans: 50 seconds)

Im using basic velocity and acceleration formulas and I can't get the answer.

there are three types of movement: the acceleration phase, the movement woth constant velocity and the decceleration.

1.To calculate the time and distance during the acceleration and decceleration use:

[tex]a = \frac {\Delta v} {\Delta t}[/tex]

--> distance at these phases: [tex]s = \bar{v} \cdot t[/tex] with

[tex]\bar{v} = \frac {1} {2} (v_{2} - v_{1})[/tex]

2. To calculate the time of the remaining distance with constant velocity use [tex]s = v \cdot t[/tex]

3. Then sum the calculated times to get to the answer: [tex]t = t_{acc} + t_{cst. v} + t_{dec}[/tex]
 
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