- #1

martine80

- 13

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**velocity ! HELP**

1:you have a lope with an angle of 15 degrees from the horizontal plane. You throw an object with an angle of 60 degrees from the horizontal plane up the slope and the object hits the ground 25m from the starting point. . What is start velocity?

This is what I’ve done:

Y = 25m *sin(15)=6,47m

X= 25m*cos(15)=24,15m

V0y=sqrt(2*g*y)=11,26m/s

.t= voy/g=1,15

V0x=x/t=21m/s

This gives me this result

V0= sqrt(v0x^2+voy^2)=23,8 m/s

But when I check the answere I get the wrong angle?

Tan(ß)=v0y/v0x -> ß=28,28

What am I doing wrong ?