2 dimensional projectile motion with rifle and bullet

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SUMMARY

The discussion centers on calculating the time of flight and initial velocity of a bullet fired horizontally from a rifle aimed at a target 30 meters away, which strikes 1.9 cm below the aim point. The calculations yield a time of flight of 0.0623 seconds and an initial horizontal velocity of 481.77 m/s. The equations used include the kinematic equation for vertical motion and the horizontal distance formula, confirming the accuracy of the results based on the provided parameters.

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Homework Statement


A rifle is aimed horizontally at a target 30m away. The bullet hits the target 1.9cm below the aiming point. what are the bullets time of flight and the initial velocity?


Homework Equations


ax=0
g=9.8m/s^2
x0=0m
xf=30m
y0=0m
yf=.019m
v0x=?
vfx=0m/s
v0y=0
vfy=0
t=?

The Attempt at a Solution



Here is a little picture i drew to visualize everything

CygLmK9.png


.019=v0y*t +1/2*g*t^2
.019=4.9*t^2
sqrt(.019/4.9)=t
t=.0623s

30m=v0x*t +1/2*ax*t62
30m=v0x*.0623s
v0x=481.77m/s

Is this correct? It seems about right. I have a small time, and a high velocity. I just want to make sure that I'm right.
 
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Looks good!
 

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