Solving x3-x-2 for the X-Axis: Newton's Method

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To find where the graph of f(x) = x^3 - x - 2 crosses the x-axis using Newton's method with an initial estimate of x0 = 2, the iterative formula xi+1 = xi - f(xi)/f'(xi) is applied. The solution is approximately 1.52138, but determining the number of iterations needed for a specific accuracy, such as three decimal places, is essential. Exact values cannot be achieved, so the focus should be on how close the iterations get to the desired accuracy. Typically, one can stop iterating once the first three decimal places remain consistent across iterations. For this problem, conducting three iterations is generally sufficient to achieve the required precision.
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Homework Statement



using Newtons method with an initial estimate of x0=2, find the point where the graph f(x)=x3-x-2 crosses the x-axis

Homework Equations



xi+1 = xi - f(xi)/f'(xi)

The Attempt at a Solution



Using a function plotter, I know the answer should be around 1.52138... But how am i supposed to know how many repetitions of Newton's method is required to get x where y=0 (i.e the x-axis).
 
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Using a function plotter, I know the answer should be around 1.52138... But how am i supposed to know how many repetitions of Newton's method is required to get x where y=0 (i.e the x-axis).
Generally it will never reach the x value when y=0, so the number of repetition is often infinite. However it's different if you want say 5 correct digits or so. I don't remember very well how to find the number of repetitions but I remember that the method converges quadratically to the solution. Reading : http://en.wikipedia.org/wiki/Newton's_method will certainly help you.
 
I had a look but still couldn't figure it out ...it wants the solution to 3 decimal places..
 
alpha01 said:

Homework Statement



using Newtons method with an initial estimate of x0=2, find the point where the graph f(x)=x3-x-2 crosses the x-axis

Homework Equations



xi+1 = xi - f(xi)/f'(xi)

The Attempt at a Solution



Using a function plotter, I know the answer should be around 1.52138... But how am i supposed to know how many repetitions of Newton's method is required to get x where y=0 (i.e the x-axis).

You aren't- no number of repetitions will give the exact value. However that is not relevant to your problem. Because you can't get an exact value, you need to think about how accurate you want the answer to be. Generally speaking, a solution is as close to the correct value as it is to the previous iteration.
 
it says give your answer "accurate to three decimal places" that is what I am unsure about... that sounds like i can just do one repetition and write the answer to 3 decimal places.. but that sounds too easy (its for my finals, it should be harder i think)
 
Then I think that 3 iterations are more than enough.
To be sure, do one iteration and keep the number you get. Do another one iteration and if the first 3 decimal places are the same, then it's done. If only the 2 first are equal, then do another iteration and you're done.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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