Solving Yo-Yo Force Problem: Find Acceleration & Friction Force

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SUMMARY

The discussion focuses on solving the Yo-Yo Force Problem, specifically calculating the acceleration and frictional force of a yo-yo with a mass of 2 kg and a moment of inertia of 0.0625 kg m². The force applied is 28 N at the top of a spindle with a radius of 0.1875 m, while the radius of the yo-yo is 0.25 m. The equations used include F - fr = ma and Torque = I * alpha, leading to the derived formula for acceleration as a = ((R * fr - r * F) * R) / I. The initial attempts to solve for the frictional force and acceleration yielded incorrect results.

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  • Understanding of Newton's second law (F = ma)
  • Knowledge of rotational dynamics, specifically torque and moment of inertia
  • Familiarity with the concept of rolling without slipping
  • Ability to manipulate equations involving angular acceleration (alpha) and linear acceleration (a)
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  • Review the principles of torque and its application in rotational motion
  • Study the relationship between linear and angular acceleration in rolling objects
  • Explore examples of similar problems involving frictional forces in rolling motion
  • Learn about the effects of different forces acting on rigid bodies in motion
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Homework Statement


A yoyo of mass m=2 kg and moment of inertia ICM=0.0625 kg m2 consists of two solid disks of radius R=0.25 m, connected by a central spindle of radius r=0.1875 m and negligible mass. A light string is coiled around the central spindle. The yoyo is placed upright on a flat rough surface and the string is pulled with a horizontal force F=28 N, and the yoyo rolls without slipping.
The force is applied at the top of the spindle; so above the center of mass.

Find the acceleration of the yo-yo.
Find the frictional force

Homework Equations


F-fr=ma
Tq=I*alpha


The Attempt at a Solution



I started taking moments about the centre of mass, which came to R*fr - r*F = Torque
Then equated this with the Inertia and alpha.
R*fr - r*F = I*alpha
Then changed alpha to a/R.
So ended up with a = ((R*fr - r*F)*R)/I
I then use the F-fr=ma equation to solve for both fr and a.
The answers i get are incorrect.
 
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Ruitker said:

Homework Statement


A yoyo of mass m=2 kg and moment of inertia ICM=0.0625 kg m2 consists of two solid disks of radius R=0.25 m, connected by a central spindle of radius r=0.1875 m and negligible mass. A light string is coiled around the central spindle. The yoyo is placed upright on a flat rough surface and the string is pulled with a horizontal force F=28 N, and the yoyo rolls without slipping.
The force is applied at the top of the spindle; so above the center of mass.

Find the acceleration of the yo-yo.
Find the frictional force

Homework Equations


F-fr=ma
Tq=I*alpha

The Attempt at a Solution



I started taking moments about the centre of mass, which came to R*fr - r*F = Torque

Are you sure the torque of the friction acts against the torque of the applied force?

Ruitker said:
Then equated this with the Inertia and alpha.
R*fr - r*F = I*alpha
Then changed alpha to a/R.
So ended up with a = ((R*fr - r*F)*R)/I
I then use the F-fr=ma equation to solve for both fr and a.
The answers i get are incorrect.

ehild
 

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