Some confusion on electron volt

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SUMMARY

The discussion clarifies the definition of an electron volt (eV) as the kinetic energy gained by an electron moving through a potential difference of one volt. It emphasizes that while the classical kinetic energy formula (1/2 mv^2) applies to non-relativistic scenarios, relativistic effects necessitate the use of the formula (gamma - 1)mc^2 for high-speed electrons. The participants confirm that regardless of the energy calculation method, an electron moving through a potential of 1 volt will always carry 1 eV of energy.

PREREQUISITES
  • Understanding of electric fields and forces (F = eE)
  • Familiarity with kinetic energy equations (1/2 mv^2 and (gamma - 1)mc^2)
  • Basic knowledge of voltage and its relationship with electric fields (Voltage = xE)
  • Concept of relativistic physics and its implications on energy calculations
NEXT STEPS
  • Study the implications of relativistic effects on particle physics
  • Learn about the derivation and applications of the relativistic energy formula (gamma - 1)mc^2
  • Explore the relationship between electric fields and potential differences in more complex systems
  • Investigate practical applications of electron volts in particle accelerators and semiconductor physics
USEFUL FOR

Students and educators in physics, electrical engineers, and anyone interested in the principles of energy transfer in electric fields and relativistic mechanics.

dragonlorder
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Homework Statement


I learned that by definition, one electron volt is the kinetic energy an electron would have moving between 1 voltage difference. if an electron moves between voltage of 1 million volts,then K = 1MeV, for example, but the problem is K is expressed in 1/2mv^2 or the relativistic one (gamma-1)mc^2

Homework Equations


The Attempt at a Solution

 
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In an electric field E the electron experiences a force F = e*E
Due to this force the electron moves a distance x, and the work done W = e*x*E.
This work produces kinetic energy in electron = 1/2*m*v^2
If the electric field is uniform Voltage = x*E
 
rl.bhat said:
In an electric field E the electron experiences a force F = e*E
Due to this force the electron moves a distance x, and the work done W = e*x*E.
This work produces kinetic energy in electron = 1/2*m*v^2
If the electric field is uniform Voltage = x*E

oh, so its defined in classical sense. I thought that since relativistic one was correct, so it might be the relativistic energy, but no. Thanks ~
 
No, for relativistic energies the relativistic formulas must be used.

1/2 m v^2 only works in non-relativistic situations.
 
Redbelly98 said:
No, for relativistic energies the relativistic formulas must be used.

1/2 m v^2 only works in non-relativistic situations.

yea, later I found out any electron moving through 1V, must carry 1eV energy by definition, doesn't depend on which formula I use. In high speed, relativistic, of course
 

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